Comments on: A rather difficult brain teaser

By: Charlie

Charlie — Fri, 11 May 2012 07:29:38 +0000

Nevermind it wouldn’t work with the princess being a year older they would have to be the same age for it to work, that way when the princess gets a year older and with the riddle in mind it would go.
princess: 2×3=6 6\2=3
The prince and princess would be the same age with that kind of math as that’s what the riddle says times the age by two as that is twice the age, and then divide by two and that is half the age.

Why make the riddle so difficult by doing harder math? All you had to do was multiply by 2 then divide by 2 by using any number it would all be the same answer. The princess and prince are the same age.

By: Charlie

Charlie — Fri, 11 May 2012 07:09:06 +0000

Hey lets say that the princess is 1 year old, and the prince will be as old as the princess when she is twice as old as 1 year but half of her current age. So the princess would be 2 years old and the prince is 1 year old. Maybe they are brother and sister.

By: Scott

Scott — Sun, 15 Apr 2012 13:48:07 +0000

Myself of course! Haha.

By: Dan

Dan — Sun, 15 Apr 2012 04:14:01 +0000

@Scott Who are you miffed at? I didn’t say you weren’t allowed to use pen and paper

By: Scott

Scott — Sat, 14 Apr 2012 18:53:45 +0000

I’m extremely miffed, I was trying to do this riddle in my head and came up with 4 & 3, 8 & 6, 16 & 12 but couldn’t quite tie it all together. I didn’t think we were ‘allowed’ to use a pen and paper!

By: sameh

sameh — Thu, 22 Mar 2012 18:06:53 +0000

the princess’s age in the past – the difference in their ages = the prince’s age in the past
the prince age in the past *2 = the princess’s age in the future
the princess’s age in the future – the difference in their ages = the prince’s age in the future , which is the princess’s age in the present
so if the princess’s age is a and the prince’s age is b
a = ((((a+b)/2)-(a-b))*2 )-(a-b)

By: babu

babu — Tue, 13 Mar 2012 09:52:46 +0000

Ans -4 is very complicated you can solve it very easily by using algebraic equations.

x-y=d
2z-x=d
(x+y)2 – z =d

y=3d
x=4d

By: Tom

Tom — Sun, 19 Feb 2012 23:59:51 +0000

Everyone doing this in such a heavy-handed way. You can solve with just 2 variables, the Princes age, and the difference between their ages (diff). Read it through and form the simultaneous equation, putting the equals before “when the princess was half the sum…”

(Prince + diff + diff)/2 + diff = (Prince + Prince + diff)/2.

Double both sides

Prince + (4 x diff) = (2 x Prince) + diff

Prince = 3 differences.

So we can’t know their ages, only that the Princess is older than the Prince by 1/3 his age. I like the riddle, the question should be “what can we know about their ages?”

By: thanksgiving

thanksgiving — Sat, 04 Feb 2012 19:44:39 +0000

they are both the same age. instead oif cheaking your work by plugging varibles back into the equation, try checking it with the actual word problem.

A princess is as old as the prince will be when the princess is twice the age that the prince was when the princess’s age was half the sum of their present ages.
so if the price and princess are both zero the riddle still works this should work if you solved it algebraically.

those who said it doesnt matter what ages they were just as long as it followed a 4:3 ratio are wrong because the riddle deals with past present or future and as soon as they get a year older the ratio would no longer be present. ex. the princess is 40 and the prince is 30 woulnd work because one year later they would be 41 and 31. that is why they must be the same age because then even after they get a year older their ages will still follow the same ratio.

By: jonni

jonni — Tue, 10 Jan 2012 09:16:17 +0000

I GIVE UPPPP!after all it’s not lyk the answer its the code-word to heaven,,or is it??????